In: Statistics and Probability
Group 1 | Group 2 | Group 3 | Group 4 |
60 | 98 | 96 | 47 |
44 | 96 | 46 | 47 |
54 | 90 | 72 | 57 |
86 | 54 | 53 | 95 |
82 | 96 | 60 | 92 |
78 | 53 | 46 | 95 |
79 | 68 | 61 | 64 |
50 | 90 | 49 | 72 |
53 | 34 | 42 | 71 |
88 | 91 | 53 | 63 |
69 | 65 | 66 | 74 |
56 | 36 | 61 | 46 |
94 | 70 | 96 | 38 |
41 | 48 | 100 | 80 |
70 | 54 | 99 | 92 |
88 | 60 | 76 | 93 |
67 | 77 | 81 | 95 |
65 | 77 | 67 | 51 |
93 | 81 | 64 | 84 |
65 | 53 | 77 | 92 |
93 | 96 | 73 | 62 |
56 | 47 | 49 | 47 |
84 | 32 | 84 | 86 |
74 | 76 | 70 | 74 |
37 | 41 | 95 | 74 |
77 | 86 | 84 | 77 |
34 | 91 | 57 | 86 |
43 | 71 | 92 | 99 |
87 | 64 | 93 | 91 |
36 | 55 | 61 | 96 |
58 | 59 | 42 | 99 |
2. Is there an appropriate alternative statistical analysis method to answer question 1? Justify. If yes, perform the alternative analyses
I have done the ANOVA test for the first question but I do not know about the second question. Please answer both questions so I can make sure it is right! thank you!
As an alternative statistical analysis method, one can perform paired t tests to check which means are significantly different.
Since P-value for all 6 tests are > 0.05, so at 5% level of significance, we can conclude that there is no significant difference in means of four groups.