In: Statistics and Probability
| Group 1 | Group 2 | Group 3 | Group 4 | 
| 60 | 98 | 96 | 47 | 
| 44 | 96 | 46 | 47 | 
| 54 | 90 | 72 | 57 | 
| 86 | 54 | 53 | 95 | 
| 82 | 96 | 60 | 92 | 
| 78 | 53 | 46 | 95 | 
| 79 | 68 | 61 | 64 | 
| 50 | 90 | 49 | 72 | 
| 53 | 34 | 42 | 71 | 
| 88 | 91 | 53 | 63 | 
| 69 | 65 | 66 | 74 | 
| 56 | 36 | 61 | 46 | 
| 94 | 70 | 96 | 38 | 
| 41 | 48 | 100 | 80 | 
| 70 | 54 | 99 | 92 | 
| 88 | 60 | 76 | 93 | 
| 67 | 77 | 81 | 95 | 
| 65 | 77 | 67 | 51 | 
| 93 | 81 | 64 | 84 | 
| 65 | 53 | 77 | 92 | 
| 93 | 96 | 73 | 62 | 
| 56 | 47 | 49 | 47 | 
| 84 | 32 | 84 | 86 | 
| 74 | 76 | 70 | 74 | 
| 37 | 41 | 95 | 74 | 
| 77 | 86 | 84 | 77 | 
| 34 | 91 | 57 | 86 | 
| 43 | 71 | 92 | 99 | 
| 87 | 64 | 93 | 91 | 
| 36 | 55 | 61 | 96 | 
| 58 | 59 | 42 | 99 | 
2. Is there an appropriate alternative statistical analysis method to answer question 1? Justify. If yes, perform the alternative analyses
I have done the ANOVA test for the first question but I do not know about the second question. Please answer both questions so I can make sure it is right! thank you!
As an alternative statistical analysis method, one can perform
 paired t tests to check which means are significantly
different.


Since P-value for all 6 tests are > 0.05, so at 5% level of significance, we can conclude that there is no significant difference in means of four groups.