Question

In a normal distribution, what percent of scores are in T-score of 65 or higher?

Answer 1

For a normally distributed variable, first, we may conclude the t score into a standard normal z score, using the formula:

T = Z(10) + 50

i.e 65 = Z(10) + 50

Z(10) = 15

Z = 1.5

We are asked to find

From standard normal table, since we only obtain the less than probabilities,

= 1 - 0.93319

= 0.06681

Percent of scores in T-score of 65 or higher = 0.06681