In: Statistics and Probability
In order to do this, a sample of 15 children is selected and the data are given below.
Age (in years) |
Height (inches) |
7 |
47.3 |
8 |
48.8 |
5 |
41.3 |
8 |
50.4 |
8 |
51 |
7 |
47.1 |
7 |
46.9 |
7 |
48 |
9 |
51.2 |
8 |
51.2 |
5 |
40.3 |
8 |
48.9 |
6 |
45.2 |
5 |
41.9 |
8 |
49.6 |
ANSWER
x | y |
7 | 47.3 |
8 | 48.8 |
5 | 41.3 |
8 | 50.4 |
8 | 51 |
7 | 47.1 |
7 | 46.9 |
7 | 48 |
9 | 51.2 |
8 | 51.2 |
5 | 40.3 |
8 | 48.9 |
6 | 45.2 |
5 | 41.9 |
8 | 49.6 |
a)
This shows that there is positive linear relation
b)
Using Excel
data -> data analysis -> regression
SUMMARY OUTPUT | |||||
Regression Statistics | |||||
Multiple R | 0.96962237 | ||||
R Square | 0.940167541 | ||||
Adjusted R Square | 0.935565044 | ||||
Standard Error | 0.917919402 | ||||
Observations | 15 | ||||
ANOVA | |||||
df | SS | MS | F | Significance F | |
Regression | 1 | 172.115845 | 172.115845 | 204.2733701 | 2.50199E-09 |
Residual | 13 | 10.95348837 | 0.842576029 | ||
Total | 14 | 183.0693333 | |||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | |
Intercept | 27.9140 | 1.3751 | 20.2996 | 0.0000 | 24.9432 |
x | 2.7395 | 0.1917 | 14.2924 | 0.0000 | 2.3254 |
y^ = 27.914 + 2.7395* x
d)
R^2 = 0.9402
hence 94.02 %
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