In: Chemistry
What is the pH of a solution of 50.0 g A- (FM= 134.32 g/mol) mixed with 200 mL 1.2 M HCl? (Ka = 5.67 x 10-7)
moles of A- = 50 / 134.32 = 0.372 mol
moles of HCl = 200 x 1.2 / 1000 = 0.240 mol
Ka = 5.67 x 10^-7
pKa = -log Ka = 6.25
A- + HCl ------------------> HA + Cl-
0.372 0.240 0 0
0.132 0 0.240
pH = pKa + log [salt / acid]
= 6.25 + log [0.132 / 0.240]
pH = 5.99