What is the pH of a solution containing 0.12 mol/L of NH4Cl and 0.03 mol/L of...

What is the pH of a solution containing 0.12 mol/L of NH4Cl and 0.03 mol/L of NaOH (pka of NH4+/NH3 is 9.25)?

Expert Solution

NH₄⁺Cl^- + NaOH ---> NH₃ + H₂O + NaCl

0.12 0.03 0 initial

0.09 0 0.03 final

it forms bufferr.

pH= pKa + log {[NH3]/ [NH4Cl]}

pH = 9 .25 + log (0.03/0.09)

=9.25 + (-0.48)

= 8.77

Answer: 8.77

queen_honey_blossom answered 5 months ago

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