Question

In: Physics

Use method of variation of parameters to solve y'' + y = sin^2(x)

Use method of variation of parameters to solve

y'' + y = sin^2(x)

Solutions

Expert Solution

The given differential equation is
  
And the homogeneous part of the equation is given by
  
This is a 2nd order differential equation, so, it must have two linearly independent solutions.
And the linearly independent solutions of the homogeneous part of the equation are

  
And so, the Wronskian of these two Linearly independent solutions is
  
So, we have
  

And if we choose the particular solution

then,
  
where,
   
So, putting the values, we get
  

So, the particular solution is
   



So, the general solution is

  
where, c1 and c2 are constants.


Related Solutions

use the method of variation of parameters to solve y''(x)-2y'(x)=exp(x)*sin(x)
use the method of variation of parameters to solve y''(x)-2y'(x)=exp(x)*sin(x)
Solve the differential equation by variation of parameters. y''+ y = sin^2(x)
Solve the differential equation by variation of parameters. y''+ y = sin^2(x)
Solve by variation of parameters. y''+4y =sin(2x) y'''-16y' = 2
Solve by variation of parameters. y''+4y =sin(2x) y'''-16y' = 2
Use the variation of parameters method to solve the differential equation: y''' - 16y' = 2
Use the variation of parameters method to solve the differential equation: y''' - 16y' = 2
use variation of parameters to solve y''+y'-2y=ln(x)
use variation of parameters to solve y''+y'-2y=ln(x)
Solve using variation of parameters. y′′ + y = sec2(x)
Solve using variation of parameters. y′′ + y = sec2(x)
Solve : y''+2y'+y=e^-x + sinx by Undetermined Coefficients method and Variation of Parameters
Solve : y''+2y'+y=e^-x + sinx by Undetermined Coefficients method and Variation of Parameters
($4.6 Variation of Parameters): Solve the equations (a)–(c) using method of variation of parameters. (a) y''-6y+9y=8xe^3x...
($4.6 Variation of Parameters): Solve the equations (a)–(c) using method of variation of parameters. (a) y''-6y+9y=8xe^3x (b) y''-2y'+2y=e^x (secx) (c) y''-2y'+y= (e^x)/x
Solve the following equation using the method of variation of parameters : x2 y'' − 2y...
Solve the following equation using the method of variation of parameters : x2 y'' − 2y = 3x2 − 1, x > 0.
Solve the differential equation by variation of parameters. y'' + 3y' + 2y = cos(ex) y(x)...
Solve the differential equation by variation of parameters. y'' + 3y' + 2y = cos(ex) y(x) = _____.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT