Question

In: Computer Science

The following code fragment is expressed in arm assembly code.Fill in the blanks, so that...

The following code fragment is expressed in arm assembly code. Fill in the blanks, so that it is equivalent to the following C code.

int counter;

int x = 5;

int y = 6;

for (counter =10; counter >0;counter--)

IF(X==Y)

Y = Y + 1 ;

ELSE

Y = Y + 2}

Fill in the blanks in the following code:

MOV__________ ;loop counter into r0-ten times round the loop

MOV__________ ;Value of y loaded into r1

MOV__________ ;Value of x loaded into r2

Next CMP ____________ ;assume r1 contains y and r2 contains x: compare them

BNE ____________ ;if not equel then branch to the else part

ADD ____________ ;if equal fall through to here and add one to y

B _____________ ;now skip past the else part

plus2 ______________ ;ELSE part add 2 to y

counter ______________ ;decrement loop counter

BNE _____________ ;continue until all done

please fill out the blanks with assembly code according to C code above

Solutions

Expert Solution

Here is the c Langauage code:

#include

int main() {
int counter;

int x = 5;

int y = 6;

for (counter =10; counter >0;counter--)
{
if(x==y)
{
y=y+1;
}
else
{
y=y+2;
}
}
}

_____________________________________________________________

Ans here is the equivalent assembly code:

.file "Test.c"

.def ___main; .scl 2; .type 32; .endef

.text

.globl _main

.def _main; .scl 2; .type 32; .endef

_main:

pushl %ebp

movl %esp, %ebp

andl $-16, %esp

subl $16, %esp

call ___main

movl $5, 4(%esp)

movl $6, 8(%esp)

movl $10, 12(%esp)

jmp L2

L5:

movl 4(%esp), %eax

cmpl 8(%esp), %eax

jne L3

addl $1, 8(%esp)

jmp L4

L3:

addl $2, 8(%esp)

L4:

subl $1, 12(%esp)

L2:

cmpl $0, 12(%esp)

jg L5

movl $0, %eax

leave

ret

.ident "GCC: (tdm-1) 4.9.2"


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