a 1.015-g sample of KHP (204.23 g/mol) is dissolved in water and tirated with 24.55 mL...

a 1.015-g sample of KHP (204.23 g/mol) is dissolved in water and tirated with 24.55 mL of NaOH solution to a phenolphthalein endpoint. Calculate the molarity of the NaOH solution.

Expert Solution

KHP is potassium hydrogen phthalate is an acidic compound. Its molar mass is 204.23 g/mol and molecular formula is C₈H₅KO₄.

KHC₈H₄O₄ + NaOH -----> KNaC₈H₄O₄ + H₂O
Moles of KHP = 1.015 gm KHP * 1 mol KHP / 204.23 g/mol KHP

= 0.00496 moles = 0.005 moles of KHP

Moles of NaOH = Moles of KHP = 0.005 moles of NaOH (according to above chemical reaction)

24.55 mL solution contains = 0.005 moles of NaOH

so, 1 mL solution = 0.005/24.55 = 0.000204 moles NaOH per mL

Hence, 1000 mL (=1 L) solution will contain = 0.000204 *1000

= 0.204 moles/mL NaOH

queen_honey_blossom answered 5 months ago

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