A particular laser pointer emits a beam with an average power of 5.00 mW, and the...

A particular laser pointer emits a beam with an average power of 5.00 mW, and the beam has a circular cross-section with a diameter of 3.00 mm. The beam is linearly polarized. The average intensity of the light is 707.7 W/m². Determine the following.

(a) the amplitude of the oscillating electric field in the laser beam (V/m)

(b) the amplitude of the oscillating magnetic field in the laser beam (T)

Solutions

Expert Solution

Given

I = 707.7 W/m^2

a)
let Emax is the amplitude of the oscillating electric field in the laser beam.

Intensity of light wave, I = Emax^2/(2*c*mue)

Emax = sqrt(2*c*mue*I)

= sqrt(2*3*10^8*4*pi*10^-7*707.7)

= 730.5 V/m

b) we know, Bmax = Emax/c

= 740.5/(3*10^8)

= 2.47*10^-6 T

genius_generous answered 1 year ago

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