In: Statistics and Probability
A poll of 2017 randomly selected adults showed that 92% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e).
Test of p=0.93 vs p≠0.93 | ||||||
Sample |
X |
N |
Sample p |
95% CI |
Z-Value |
P-Value |
---|---|---|---|---|---|---|
1 |
1849 |
2,017 |
0.916708 |
(0.900860,0.932556) |
−2.34 |
0.019 |
a) Is the test two-tailed, left-tailed, or right-tailed?
b) What is the test statistic?
c) What is the P-value?
d) What is the null hypothesis and what do you conclude about it?
A. H0: p=0.93
B. H0: p>0.93
C. H0: p≠0.93
D. H0: p less than 0.93
e) Choose the correct answer below.
A. Reject the null hypothesis because the P-value is greater than the significance level, alpha.
B. Fail to reject the null hypothesis because the P-value isgreater than the significance level, alpha.
C. Reject the null hypothesis because the P-value is less than or equal to the significance level, alpha.
D. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, alpha.
f) What is the final conclusion?
A.There is sufficient evidence to support the claim that 93% of adults own a cell phone.
B.There is not sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone.
C.There is sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone.
D. There is not sufficient evidence to support the claim that 93% of adults own a cell phone.