Balance the reaction in acidic solution. MnO4- + Al ----> Mn2+ + Al3+

Balance the reaction in acidic solution.

MnO4- + Al ----> Mn2+ + Al3+

Solutions

Expert Solution

Given unbalanced reaction is

MnO₄^- + Al Mn²⁺ + Al³⁺

By identufying redox couple , we wil write half reactions

Oxidation : Al Al³⁺

Reduction : MnO₄^- Mn²⁺

Now , balancing the oxygen atom , we will have

Oxidation : Al Al³⁺

Reduction : MnO₄^- Mn²⁺ +4H₂O

Now balancing the hydrogen atom

Oxidation : Al Al³⁺

Reduction : MnO₄^- +8H⁺ Mn²⁺ +4H₂O

Now balancing the charge

Oxidation : Al Al³⁺ + 3e

Reduction : MnO₄^- +8H⁺ + 5e Mn²⁺ +4H₂O

Now making electron gain equal to electron lost

Oxidation : 5Al 5 Al³⁺ + 15e

Reduction : 3MnO₄^- + 24H⁺ + 15e 3Mn²⁺ + 12H₂O

Now adding half reactions together , So

5Al + 3 MnO₄^- + 24H⁺ + 15e 5 Al³⁺ + 15e + 3Mn²⁺ + 12H₂O

We get final balanced reaction in acidic solution

5Al + 3MnO₄^- +24H⁺ 5Al³⁺ + 3Mn²⁺ + 12H₂O

queen_honey_blossom answered 1 year ago

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