Question

In: Statistics and Probability

Find each probability P(X; λ) using Table C in Appendix A. a. P(10; 7) b. P(9; 8) c. P(3; 4) Data from in Table C Appendix A

Find each probability P(X; λ) using Table C in Appendix A.

a. P(10; 7)

b. P(9; 8)

c. P(3; 4)

 

Data from in Table C Appendix A

 

Solutions

Expert Solution

a)

Obtain the probability P(X; λ) when P(10;7) by using Table C in Appendix A.

From the “Appendix A Table C, The Poisson Distribution”, the probability P(10;7)corresponding to X = 10, and λ = 7 is 0.071.

 

b)

Obtain the probability P(X;λ) when P(9;8) by using Table C in Appendix A.

From the “Appendix A Table C, The Poisson Distribution”, the probability P(9;8) corresponding to X = 9, and λ = 8 is 0.1241.

 

c)

Obtain the probability P(X; λ) when P(3;4) by using Table C in Appendix A.

From the “Appendix A Table C, The Poisson Distribution”, the probability P(3;4) corresponding to X = 3, and λ = 4 is 0.1954.


Related Solutions

Find each probability P(X; λ), using Table C in Appendix A. a. P(5; 4) b. P(2; 4) c. P(6; 3) Data from in Table C Appendix A
Find each probability P(X; λ), using Table C in Appendix A.a. P(5; 4)b. P(2; 4)c. P(6; 3)Data from in Table C Appendix A
For the following data set, X: 9, 6, 8, 3, 8, 9, 3, 4, 3, 7:...
For the following data set, X: 9, 6, 8, 3, 8, 9, 3, 4, 3, 7: Calculate: 1. Variance 2. Mode 3. Mean 4. Mean Average Deviation (MAD) about the mean 5. Median
a = [3, -4, 7] b = [-6, 9, 8] c = [4, 0, 8] d...
a = [3, -4, 7] b = [-6, 9, 8] c = [4, 0, 8] d =[7, 1, 7] e = [3, -5, 2, 1] f =[5, -7, -3, 6] g = [3, -4, 4, 3] P = Projection of ex. C = |g|(gf/gf) C = gf/|f| ex. P g --> f = Cgf = C(gf/f) (1/|f|) (f) =( gf/ff)(f) Find a. Pg --> f b. Pa --> 3b + e Find (cross multiply) a. ||a X b|| b. ||g...
Find the (probability generating function) p.g.f.’s of the following distributions:[3+3=6] •P(X=x) =(exp(−λ)λ^x)/((1−exp(−λ))x!) , for x= 1,2,3,...,...
Find the (probability generating function) p.g.f.’s of the following distributions:[3+3=6] •P(X=x) =(exp(−λ)λ^x)/((1−exp(−λ))x!) , for x= 1,2,3,..., and λ >0. •P(X=x) =((pq)^x)(1−q^(N+1))^−1,for x= 0,1,..., N; where 0 < p < 1, p+q= 1.
Using the same data… 2 3 4 4 4 6 6 6 7 8 8 9...
Using the same data… 2 3 4 4 4 6 6 6 7 8 8 9 10 10 11 12 16 16 28 46 (d) [5 pts] Determine the 5# summary. (e) Determine the lower and upper fence to determine if there are any outliers. (f) Draw and carefully label a modified boxplot for this data. (g) What is the shape of the distribution (symmetric, skewed left, or skewed right). Explain.
3, 7, 8, 5, 6, 4, 9, 10, 7, 8, 6, 5 Using the previous question...
3, 7, 8, 5, 6, 4, 9, 10, 7, 8, 6, 5 Using the previous question 's scores, If three points were added to every score in this distribution, what would be the new mean? If three points were added to every score in this distribution, what would be the new standard deviation. Remember, you have already calculated population standard deviation in a previous problem. This problem requires two answers.
3. Using the same table from class (or Appendix C in Priviterra, pp. C1-C4), find the...
3. Using the same table from class (or Appendix C in Priviterra, pp. C1-C4), find the proportion under the standard normal curve that lies between each of the following points: The mean and z =+2.00 The mean and z = 0 z = -1.96 and z = -1.64 z = -.82 and z = + .82 z = +0.50 and z = +1.90
x 2 8 5 9 4 3 9 6 7 8 y 3 6 5 7...
x 2 8 5 9 4 3 9 6 7 8 y 3 6 5 7 9 7 4 6 9 9 -5.48x + 0.17 5.48x + 0.17 -0.17x + 5.48 0.17x + 5.48
A = [4, 5, 9] B = [-4, 5, -7] C = [2, -7, -8, 5]...
A = [4, 5, 9] B = [-4, 5, -7] C = [2, -7, -8, 5] D = [1, -9, 5, -3] E = [3, 3, -1] Uz = 1/|z| ^z d(X,Y) = (Rθ) d = diameter R = Radius θ = Theta Find a. Uc b. d (D, C) c. Let P = B + 3E, UP = d. A x B e. 3B x E f. C x D
Using Appendix C-1 or Appendix C-2 find the p-value for each test statistic. (Round your answers...
Using Appendix C-1 or Appendix C-2 find the p-value for each test statistic. (Round your answers to 4 decimal places.) Test Statistic p-value (a) Right-tailed test z = +2.59 (b) Left-tailed test z = –1.02 (c) Two-tailed test z = –1.74
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT