In: Statistics and Probability
A.: a)
Percentage of persons with temperature in excess of 100.6:
μ = 98.23
σ = 0.61
standardize x to z = (x - μ) / σ
P(x > 100.6) = P( z > (100.6-98.23) / 0.61)
= P(z > 3.93) = 0.000032 (0.0032 %)
B. From the normal probability table, P( z > 1.645) = 0.05
z = (x - μ) / σ
1.645 =( x-98.23) / 0.61
x = (1.645)(0.61)+ 98.23 = 99.23 F
a)
The percentage of normal and healthy person is considered to have fever is.01% Yes, because there is a small probability that a normal and healthy person would be considered to have a fever.
b) if we were only 5.0% of healthy people to exceed it. then minimum temperature is99.23 F