Question

1. What volume of sulfur trioxide gas is produced from 28.0 L of oxygen gas? The volume of each gas is measured at 875 ∘C and 1.00 atm pressure.

SO2(g)+O2(g)→SO3(g)

Express your answer with the appropriate units.

2. If 50.0 L of hydrogen chloride gas reacts with 10.0 L of oxygen gas, what is the volume of chlorine gas produced? Assume all gases are at the same temperature and pressure.

HCl(g)+O2(g)→Cl2(g)+H2O(g)

Express your answer with the appropriate units.

Answer 1

1)
the baalanced reaction is
2SO2 + O2 --> 2SO3

since,
pressure, temperature is kept constant
number of mole is directly propional to volume
this problem we will solve by volume

according to above balanced reaction
1 mole of O2 give 2 mole of SO3
so,
1 L of O2 give 2 L of SO3
28 L of O2 give (2*28) L of SO3
volume of SO3 produce = (2*28) L
volume of SO3 produce = 56 L

2)
the balanced reaction is
4HCl + O2 --> 2Cl2 + 2H2O

since,
pressure, temperature is kept constant
number of mole is directly propional to volume
this problem we will solve by volume

according to above balanced reaction
4 mole of HCl require 1 mole of O2
4 L of HCl require 1 L of O2
1 L of HCl require 1/4 L of O2
50 L of HCl require (1/4)*50 L of O2
volume of O2 required = (1/4)*50
= 12.5 L
but, we have only 10 L of O2
so, O2 is limiting reagent

again, according to above balanced reaction
1 mole of O2 give 2 mole of Cl2
1 L of O2 give 2 L of Cl2
10 L of O2 give (2*10) L of Cl2
volume of O2 produced = (2*10) L
volume of O2 produced = 20 L