Question

(Steps)Plot a stress-strain curve using Matlab(cross sectional area 30 mm^2)

Force (kN)	Strain
8.59E-02	0.000054
2.55E-01	0.000054
2.82E-01	0.000054
2.95E-01	0.000054
3.09E-01	0.000054

Step 1:Divide the applied force by the cross-sectional area to be able to get applied stress ?. Also, convert to MPa.

2. Graph the stress-strain curve with strain as the abscissa and stress as the ordinate.

3. Make sure to label the axes with the variable (? or ?) and the correct units.

4. Add a title.

5. Calculate and label the yield stress ?? and ultimate stress ?? on the stress-strain curve.

6. Compute the elasticity ? in GPa. Do this by solving for the slope of the initial linear portion of the stress-strain curve. Please label it on the curve.

Answer 1

MATLAB CODE:

clc
clear all
close all

Strain = [0.000054;0.000054;0.000054;0.000054;0.000054];
Force = [8.59e-02;2.55e-01;2.82e-01;2.95e-01;3.09e-01]*10e3; % Force units are in Newton
Area = 30*((1e-03)^2); % Cross sectional area units are in square meters
Stress = Force/Area; % Stress units are in Pascal
Stress = Stress*1e-06; % Converting Stress units from Pascal to Mega Pascal i.e.,Mpa

Table1 = table(Force,Strain);
Table2 = table(Stress,Strain);
disp(Table1)
disp(Table2)

plot(Strain,Stress,'ro') % Plots the points
grid on
xlabel('Strain')
ylabel('Stress( Mpa)')
title('Stress-Strain Curve')
xlim([0.000053 0.000055])

figure

plot(Strain,Stress,'r') % Plot produced by joining the points
grid on
xlabel('Strain')
ylabel('Stress( Mpa)')
title('Stress-Strain Curve')
xlim([0.000053 0.000055])

OUTPUT:

Force Strain
_____ _______

859 5.4e-05
2550 5.4e-05
2820 5.4e-05
2950 5.4e-05
3090 5.4e-05

Stress Strain
______ _______

28.633 5.4e-05
85 5.4e-05
94 5.4e-05
98.333 5.4e-05
103 5.4e-05