In: Chemistry
Find the ΔH for the reaction below, given the following reactions and subsequent ΔH values: (8 pts)
Zn(s) + 1/8S8(s) + 2O2(g) → ZnSO4(s)
Zn(s) + 1/8S8(s) →
ZnS(s)
ΔH = -183.92 kJ
2ZnS(s) + 3O2(g) → 2ZnO(s) +
2SO2(g)
ΔH = -927.54 kJ
2SO2(g) + O2(g) →
2SO3(g)
ΔH = -196.04 kJ
ZnO(s) + SO3(g) → ZnSO4
(s) ΔH
= -230.32 kJ
Zn(s) + 1/8S8(s) + 2O2(g) → ZnSO4(s) ΔH = ??
Zn(s) + 1/8S8(s) → ZnS(s) ΔH1 = -183.92 kJ rxn(1)
ZnS(s) + 3/2 O2(g) → ZnO(s) + SO2(g) ΔH2 = -463.77 kJ rxn (2)
SO2(g) + 1/2O2(g) → SO3(g) ΔH3 = -98.02 kJ rxn(3)
ZnO(s) + SO3(g) → ZnSO4 (s) ΔH4 = -230.32 kJ rxn (4)
add all reaction
Zn(s) + 1/8S8(s) + 2O2(g) → ZnSO4(s) ΔH = ΔH 1 + ΔH2 + ΔH3 + ΔH4
ΔH = ΔH 1 + ΔH2 + ΔH3 + ΔH4
ΔH = -183.92 -463.77 -98.02 -230.32
ΔH = -976.03 kJ