Question

In: Physics

We assumed that the spring is ideal. In reality, as you stretch and compress the spring,...

We assumed that the spring is ideal. In reality, as you stretch and compress the spring, frictional forces of the spring come into play. Explain how the frictional forces of the spring would or could affect your measurements.

Solutions

Expert Solution

Hello buddy!

Let me explain to you how the frictional forces of a spring affect our measurements while compressing or stretching!

By using Hooke's law, we know that the force exerted while stretching or compressing a spring is given by

F = - k x

The potential energy stored by a compressed spring is given by Us =

gravitational potential energy of an object at a height h, above an arbitrarily defined zero point is

Ug=mgh

m = mass of object and g = acceleration due to gravity 9.8 m/s^2

Forces due to friction causes a significant effect in this case, so we will try to account for it. The frictional force on an object moving horizontally is

Ffx = μmg =ma

µ is the coefficient of friction and a is the acceleration. Since acceleration is the time derivative of velocity, and we can cancel the mass above. Thus the above equation can be written as,

while on an incline plane, the frictional force is given by

Ff =μmgcosθ

= angle of slope/incline

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