determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following: O3...

determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following: O3 & H3O+ & NF3

Expert Solution

Solution:

A) O3

Ozone is sp2 hybridized due to 2 bond pairs and 1 lone pairs. Thus, electronic geometry is trigonal planar and shape will be bent.

Electron-group geometry = Trigonal planar

Molecular shape = Bent

Bond angle = 116 °

B) H3O+

The hybridization of central oxygen in H3O+ is sp3 and it containd three bond pairs and one lone pairs. Therefore,

Electron-group arrangement = Tetrahedral

Molecular shape = Pyramidal

Bond angle = 109.5 °

C) NF3

Nitrogen in NF3 is sp3 hybridized. It has three bond pairs and one lone pairs. Due to lone pair its shape is compressed from tetrahedral to pyramidal.

Electron-group geometry = Tetrahedral

Molecular shape = Pyramidal

Bond angle = 102°

queen_honey_blossom answered 2 years ago

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determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following: O3...

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