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In: Statistics and Probability

The operation manager at a tire manufacturing company believes that the mean mileage of a tire...

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 47,225 miles, with a standard deviation of 3178 miles. What is the probability that the sample mean would be greater than 47,050 miles in a sample of 208 tires if the manager is correct? Round your answer to four decimal places.

Solutions

Expert Solution

Solution :

Given that ,

mean = = 47225

standard deviation = = 3178

= / n = 3178 / 208 = 220.3547

P( > 47050) = 1 - P( < 47050)

= 1 - P[( - ) / < (47050 - 47225) / 220.3547]

= 1 - P(z < -0.7942)

= 1 - 0.2135

= 0.7865

Probability = 0.7865

orchestra answered 2 years ago
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