In: Finance
Lionel’s student loan of $21,500 at 3.92% compounded quarterly was amortized over 4 years with payments made at the end of every month. What was the principal balance on the loan after 3 years?
Round to the nearest cent
$ 5,693.48
Step-1:Calculation of equivalent monthly interest rate | |||||||||
(1+i1)^n1 | = | (1+i2)^n2 | Where, | ||||||
(1+i1)^3 | = | (1+0.0098)^1 | i2 | = | Quarterly Interest rate | ||||
(1+i1)^3 | = | 1.0098 | = | 3.92%/4 | |||||
1+i1 | = | 1.0098 | ^(1/3) | = | 0.0098 | ||||
1+i1 | = | 1.003256 | |||||||
i1 | = | 0.003256 | i1 | = | Monthly Interest rate | = | ? | ||
n1 | = | Month in a quarter | = | 3 | |||||
n2 | = | Quarter in a quarter | = | 1 | |||||
Step-2:Calculation of monthly payment | |||||||||
Monthly Payment | =-pmt(rate,nper,pv,fv) | Where, | |||||||
$ 484.56 | rate | = | 0.00325605 | ||||||
nper | = | 48 | |||||||
pv | = | $ 21,500 | |||||||
fv | = | 0 | |||||||
Step-3:Loan balance after 3 years | |||||||||
Loan balance after 3 years | =pv(rate,nper,pmt,fv) | Where, | |||||||
= $ 5,693.48 | rate | = | 0.00325605 | ||||||
nper | = | 12 | |||||||
pmt | = | $ -484.56 | |||||||
fv | = | 0 | |||||||