Question

In: Statistics and Probability

A. Suppose that, for a particular type of cancer, chemotherapy provides a 5-year survival rate of...

A. Suppose that, for a particular type of cancer, chemotherapy provides a 5-year survival rate of 72%.

Among 20 patients diagnosed to have this form of cancer who are just starting the chemotherapy,

find the probability that at least 15 of them survive at 5-years or longer. Round answer to 3 significant

digits.

B. A home insurance company charges $2500 for the insurance policy. The policy only covers two

kinds of claims -- minor and large. Eight percent of homeowners will file a minor claim. When this

happens the insurance company pays out $10,000. Only 1% of the population will make a large

claim. When that happens the insurance company has to pay out $150,000. What is the expected

value of this policy to the insurance company?

C. The heights of National Basketball Association (NBA) players are normally distributed with a mean of

79” (6’7”) and a standard deviation of 3.89 inches. What heights delineate the middle 80% of NBA

players? Round your answer to the nearest inch.

Solutions

Expert Solution


Related Solutions

2. The 5 year survival rate for a type of cancer is 76%. You conduct research...
2. The 5 year survival rate for a type of cancer is 76%. You conduct research on a treatment for this cancer and find that for the 96 cancer patients who had this form of cancer and were given this new treatment that after 5 years 80 were still alive. a) At the .05 level did your new treatment have any effect on the survival rate? (note: p = .092) b) How do you explain the 6.3% difference in the...
Suppose the survival time (in months) of certain type of a fatal cancer is a random...
Suppose the survival time (in months) of certain type of a fatal cancer is a random variable X with pdf f(x) = 0.1 e^^{-0.1x} , x > 0 from onset. (a) Find the probability that a patient will live less than a year from onset. (b) Find the probability that a patient will live between 6 months to 18 months from onset. (c) Find the probability that a patient will live more than two years from onset.
The survival rate of a cancer using an existing medication is known to be 30%. A...
The survival rate of a cancer using an existing medication is known to be 30%. A pharmaceutical company claims that the survival rate of a new drug is higher. The new drug is given to 15 patients to test for this claim. Let X be the number of cures out of the 15 patients. Suppose the rejection region is {8 }.≥X a. State the testing hypotheses. b. Determine the type of error that can occur when the true survival rate...
Metastasis is responsible for about 90% of cancer associated deaths. The five year survival rate comparisons...
Metastasis is responsible for about 90% of cancer associated deaths. The five year survival rate comparisons for metastatic and non-metastatic tumors in various tissues was presented in lecture 10. The prostate cancer survival rate for non-metastatic tumors is 100%, whereas for liver cancer it is 28%. Why do you think there is such a big difference in survival rates for these two cancer types when both are non-metastatic tumors? (5 points)
85-year-old female diagnosed with ovarian cancer 5 years ago. She was treated with surgery and chemotherapy....
85-year-old female diagnosed with ovarian cancer 5 years ago. She was treated with surgery and chemotherapy. Surgical treatment included bilateral salpingo-oophorectomy and total abdominal hysterectomy. At that time, the clientwas found to be BRCA1 positive. She declined any prophylactic surgery or treatment. She was subsequently diagnosed with breast cancer 18 months ago and underwent a lumpectomy of the right breast, followed by chemotherapy and radiation. Two months ago, she was diagnosed with Stage IV metastatic disease in her bones, brain,...
A patient is tested for cancer. This type of cancer occurs in 5% of the population....
A patient is tested for cancer. This type of cancer occurs in 5% of the population. The patient has undergone testing that is 90% accurate and the results came back positive. What is the probability that the patient actually has cancer? (Conditional probability)
A certain test for a particular type of cancer is known to be 95% accurate. A...
A certain test for a particular type of cancer is known to be 95% accurate. A person takes the test and the results are positive. Suppose the person comes from a population of 100,000 where 2000 people suffer from that disease. What if the person takes a second test and result is still positive, what can we conclude about his odds of having cancer?
Part 1 Binomial Distribution [Mark 20%/cancer type, 40% total mark] Five year survival chance from any...
Part 1 Binomial Distribution [Mark 20%/cancer type, 40% total mark] Five year survival chance from any cancer depends on many factors like availability of treatment options, expertise of attending medical team and more. Five year survival rate is also an important measure and it is used by medical practitioners to report prognosis to patients and family. We will be analyzing five year survival rate of two types of cancer, very aggressive and very treatable cancer and to have comparative analysis...
A screening test for prostate cancer has been shown to increase mean survival time by 5...
A screening test for prostate cancer has been shown to increase mean survival time by 5 years, and patients diagnosed via screening have demonstrated a better response to treatment than those not detected by screening. Would you determine this screening program a success? Why/why not? Provide at least 3 detailed reasons for your answer.
Suppose that a two-year bond with a principal of $100 provides coupons at the rate of...
Suppose that a two-year bond with a principal of $100 provides coupons at the rate of 6% per annum semiannually. Suppose that the zero-rates are Maturity (years) Zero Rate (%) 0.5 5.0 1.0 5.8 1.5 6.4 2.0 6.8 What is the bond's yield to maturity expressed with the continuous compounding? - please use the formulas and explain step by step
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT