In: Statistics and Probability
The effectiveness of a blood-pressure drug is being
investigated. An experimenter finds that, on average, the reduction
in systolic blood pressure is 30.3 for a sample of size 318 and
standard deviation 18.8.
Estimate how much the drug will lower a typical patient's systolic
blood pressure (using a 80% confidence level).
Enter your answer as a tri-linear inequality accurate to one
decimal place (because the sample statistics are reported accurate
to one decimal place).
< μμ <
Answer should be obtained without any preliminary rounding.
Solution:
Given that,
n = 318
= 30.3
s = 18.8
Note that, Population standard deviation()
is unknown..So we use t distribution.
Our aim is to construct 80% confidence interval.
c = 0.80
= 1- c = 1- 0.80= 0.20
/2
= 0.10
Also, d.f = n - 1 = 318 - 1 = 317
=
=
0.10
, 317 = 1.284
( use t table or t calculator to find this value..)
The margin of error is given by
E = /2,d.f.
* (
/
n)
= 1.284 * (18.8 /
318)
= 1.354
Now , confidence interval for mean()
is given by:
(
- E ) <
< (
+ E)
(30.3 - 1.354) <
< (30.3 + 1.354)
28.9 <
< 31.7