Question

At sea level, from rest to exercising at a oxygen consumption of 2 liters / min, your heart rate, ventilation and SaO2 increases by 60 beats/min, 50 l/min and 1%, respectively. You repeat the same exercise at 5000m. Here, heart rate increases by 90 beats/min and ventilation increase by 80 l/min; your SaO2 decreases by 15%. Explain these changes.

Answer 1

At sea level his heart rate increases by 60 beats per minute and 50 l/ min O2 all these are adaptive mechanism taking place in human. Body to provide enough oxygen for the muscle and body tissues while exersice is done . Our body require more O2 so heart rate increases to compensate the need .

In the second case heart rate increases by 90 beats and ventilation increase by 80l/ min . These change s are because at higher attitude the oxygen molecules are further apart as there is less pressure present at higher attitudes. This means the the individual who is doing Exersice at the sea level will get more amount of oxygen when compared to the individual at 5000m .

So the cardiovascular system of the person doing Exersice at 5000 m height has to compensate for the oxygen for Exersice + low oxygen concentration .

So his cardiovascular system is increasing the heart rate

His spo2 is decreased because his body has more hemoglobin without oxygen molecules,that is the concentration of hemoglobin without O2 . So it show the reading 15% decrease

So the difference in these situation are attitude Reduce the O2 level of blood causing hypoxemia and heart rate increases to compensate it