In: Statistics and Probability
At a local store, 65 female employees were randomly selected and
it was found that their mean monthly
income was $625 with a standard deviation of $121.50. Seventy-five
male employees were also randomly
selected and their mean monthly income was found to be $667 with a
standard deviation of $168.70. Test the
hypothesis that male employees have a higher monthly income than
female employees. Use α = 0.01.
Use any method, however, follow the PHANTOMS acronym.
P - Parameter Statement
H - Hypotheses
A - Assumptions & Conditions
N - Name the Test and state the curve you're using
T - Test Statistic - Round your value to TWO decimals and state the command you used to find this value
O - Obtain the P-Value or Critical Value . State the command you are using to find these values
M - Make a Decision about the Null Hypothesis and explain why
S - State Your Conclusion About the Claim
P- male employees have a higher monthly income than female employees.
H-
Ho : µ1 - µ2 = 0
Ha : µ1-µ2 < 0
A-
population is normally distributed
Sample are random and independent
N- 2 independent sample t test
T-
Sample #1 ----> 1
mean of sample 1, x̅1= 625.00
standard deviation of sample 1, s1 =
121.5
size of sample 1, n1= 65
Sample #2 ----> 2
mean of sample 2, x̅2= 667.000
standard deviation of sample 2, s2 =
168.70
size of sample 2, n2= 75
difference in sample means = x̅1-x̅2 =
625.000 - 667.0000
= -42.0000
std error , SE = √(s1²/n1+s2²/n2) =
24.6287
t-statistic = ((x̅1-x̅2)-µd)/SE = (
-42.0000 / 24.6287 )
= -1.7053
O-
DF=133
p-value = 0.04523 [
excel function: =T.DIST(t stat,df) ]
M-
Conclusion: p-value>α , Do not reject null
hypothesis
S- There is not enough evidence to conclude that male employees have a higher monthly income than female employees.
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