Question

Question 6

Which of the following for loops will find the largest element in the array numbers, assuming numbers has already been assigned a collection of numeric values?

Question 6 options:

	largest = None for i in range(len(numbers)): if largest is None and numbers[i] > largest: largest = numbers[i]
	largest = None for i in range(numbers): if largest is None and numbers[i] > largest: largest = numbers[i]
	largest = None for i in range(len(numbers)): if largest is None or numbers[i] > largest: largest = numbers[i]
	largest = None for i in range(numbers): if largest is None or numbers[i] > largest: largest = numbers[i]

Question 7

Which of the following is the correct output from this sequence of statements?

array1 = [1, 2, 3]
array2 = [2, 3]
print((array1 + array2) * 2)

Question 7 options:

	[1, 2, 3, 2, 3, 1, 2, 3, 2, 3]
	[1, 2, 3, 2, 3]
	[1, 2, 3, 2, 3, 2, 3]
	[1, 2, 3]

Question 8

Which of the following is the correct output from this sequence of statements?

primes = [2, 3, 5, 7, 11, 13]
primes[3:] = [1, 2, 3]
print(primes[:4])

Question 8 options:

	[2, 3, 5, 7]
	[2, 3, 5]
	[3, 5, 1]
	[2, 3, 5, 1]

Question 9

Which of the following is the correct output from the following sequence of statements?

sequence = [1, 3, 5, 7, 9]
for i in range(len(sequence)):
sequence[i] = i + sequence[i]
print(sequence)

Question 9 options:

	[2, 7, 14, 23, 34]
	[1, 4, 7, 10, 13]
	[2, 6, 10, 14, 18]
	[1, 4, 9, 16, 25]

Question 10

Which of the following is the correct output from this sequence of statements?

numbers = [18, 27, 42, 13, 21, 8, 11]
print(max(numbers))

Question 10 options:

	42
	140
	7
	8

Answer 1

Question 6:

largest = None
for i in range(len(numbers)):
if largest is None or numbers[i] > largest:
largest = numbers[i]

The for loop will find the largest element in the array numbers, assuming numbers has already been assigned a collection of numeric values.

In every iteration it checks for largest and assign a list number if the condition is true.

Sample Code:

Sample run:

Code to Copy (Refer above images of code for indentation):
#example list
numbers=[1,2,10,2,4,15,8,5]
largest = None
#for loop iterate through list
for i in range(len(numbers)):
#compare and assign largest
if largest is None or numbers[i] > largest:
largest = numbers[i]
#print largest
print(largest)

Question 7:

[1, 2, 3, 2, 3, 1, 2, 3, 2, 3]

The above list is generated with the given code.

array1 = [1, 2, 3]
array2 = [2, 3]
print((array1 + array2) * 2)

(array1+array2)=[1,2,3,2,3]*2=[1,2,3,2,3,1,2,3,2,3]

So the above option is correct.

Sample run:

Question 8:

[2, 3, 5, 1]

The above list is printed with the given code. Because in the code slicing is used.

#list initialization
primes = [2, 3, 5, 7, 11, 13]
#modify above list from 3 rd index element
primes[3:] = [1, 2, 3]
#print list upto index 3
print(primes[:4])

initial list -[2,3,5,7,11,13]

primes[3:]=[1,2,3] so primes list modified as [2,3,5,1,2,3]

print(primes[:4]) prints upto index 3.

so it prints 2,3,5,1.

So the above list is printed.

Sample run:

Question 9:

[1, 4, 7, 10, 13]

The above list is printed by given code

#list initialization

sequence = [1, 3, 5, 7, 9]
for i in range(len(sequence)):

#using loop add index to value
sequence[i] = i + sequence[i]
print(sequence)

In the code, the index value is added to respective value.

1 index 0 =1+0 =1

3 index 1= 3+1=4

5 index 2=5+2=7

7 index 3=7+3=10

9 index 4=9+4=13

The final list printed is [1,4,7,10,13]

Sample run:

Question 10:

42

42 is printed because max() function return maximum value.

So in the given list 42 is highest.

numbers = [18, 27, 42, 13, 21, 8, 11] -42 maximum

Sample run: