In: Chemistry
The vapor pressure of nitric acid varies with temperature as follows.
T/oC | 0 | 20 | 40 | 50 | 70 | 80 | 90 | 100 |
P/torr | 14.4 | 47.9 | 133 | 208 | 467 | 670 | 937 | 1282 |
What is the normal boiling point and the enthalpy of vaporization?
from clasius-clepyron equation
ln(p2/p1) = DH0rxn/R[1/T1 - 1/T2]
P1 = 14.4 torr, T1 = 273.15+0 = 273.15 k
P2 = 47.9 torr, T2 = 273.15 +20 = 293.15 k
DHvap = ? kj/mol
ln(47.9/14.4) = (x/8.314)((1/273.15)-(1/293.15))
enthalpy of vaporisation = DHvap = 40.006 kj/mol
at normal boiling point, Pressure = atmospheric pressure = 1 atm = 760 torr.
ln(p2/p1) = DH0rxn/R[1/T1 - 1/T2]
P1 = 14.4 torr, T1 = 273.15+0 = 273.15 k
P2 = 760 torr, T2 = ? k
DHvap = 40.006*10^3 j/mol
ln(47.9/760) = (40.006*10^3/8.314)((1/273.15)-(1/x))
T2 = 236.1 k
normal boiling point = 273.15-236.1 = 37.05 c