Question

In: Statistics and Probability

Due to distance learning and less homework load in Peach Elementary School, parents are complaining that...

Due to distance learning and less homework load in Peach Elementary School, parents are complaining that the average screen time is more than 3 hours per day for students in Grade 1 to Grade 3. The principal randomly selected 36 students from Grade 1 - Grade 3 and statistical summary is shown below.

min

avg

max

std

3

5

8

2.5

a. Write the hypothesis in symbols or words

b. Check the two conditions for CLT.

c. Calculate the test statistics and the associated degrees of freedom

d. Use the p-value or critical value approach to make your conclusion at 5% significance level.

one tail (upper)

0.1

0.05

0.025

0.01

0.005

two tails

0.2

0.1

0.05

0.02

0.01

t value, df = 35

1.31

1.69

2.03

2.44

2.73

Solutions

Expert Solution

Solution:

Given that

n= 36 sample size

population mean

sample mean

s = 2.5 sample standard deviations

level of significance

a) To test the hypothesis

. Vs.

Hypothesis in words

Ho: The average screen time is same 3 hours per day for students in grade1 to grade 3.

Vs

Ha: The average screen time is more than 3 hours per day for students in grade1 to grade 3

b) Condition for CLT

1) The sample observation of grade 1 to grade 3 students are independent to each other.

2) The sample is drawn without replacement of the grede 1 to grade 3 students.

3) sample size of grade 1 to grade 3 students not more than 10% of the population.

c) Test statistic

t = 4.8000007

Test statistic t = 4.8000

The degree of freedom associated with the test statistic is n-1 =36-1=35

The degree of freedom =35

The t critical value at is

from t table

The t critical value =1.69

d) Decision :

t stat > t critical value

4.80 > 1.69

Reject Ho

Conclusion: Reject Ho, there is sufficient evidence to conclude that the average screen time is more than 3 hours per day for students in grade1 to grade 3.


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