In: Statistics and Probability
Due to distance learning and less homework load in Peach Elementary School, parents are complaining that the average screen time is more than 3 hours per day for students in Grade 1 to Grade 3. The principal randomly selected 36 students from Grade 1 - Grade 3 and statistical summary is shown below.
min |
avg |
max |
std |
3 |
5 |
8 |
2.5 |
a. Write the hypothesis in symbols or words
b. Check the two conditions for CLT.
c. Calculate the test statistics and the associated degrees of freedom
d. Use the p-value or critical value approach to make your conclusion at 5% significance level.
one tail (upper) |
0.1 |
0.05 |
0.025 |
0.01 |
0.005 |
two tails |
0.2 |
0.1 |
0.05 |
0.02 |
0.01 |
t value, df = 35 |
1.31 |
1.69 |
2.03 |
2.44 |
2.73 |
Solution:
Given that
n= 36 sample size
population mean
sample mean
s = 2.5 sample standard deviations
level of significance
a) To test the hypothesis
. Vs.
Hypothesis in words
Ho: The average screen time is same 3 hours per day for students in grade1 to grade 3.
Vs
Ha: The average screen time is more than 3 hours per day for students in grade1 to grade 3
b) Condition for CLT
1) The sample observation of grade 1 to grade 3 students are independent to each other.
2) The sample is drawn without replacement of the grede 1 to grade 3 students.
3) sample size of grade 1 to grade 3 students not more than 10% of the population.
c) Test statistic
t = 4.8000007
Test statistic t = 4.8000
The degree of freedom associated with the test statistic is n-1 =36-1=35
The degree of freedom =35
The t critical value at is
from t table
The t critical value =1.69
d) Decision :
t stat > t critical value
4.80 > 1.69
Reject Ho
Conclusion: Reject Ho, there is sufficient evidence to conclude that the average screen time is more than 3 hours per day for students in grade1 to grade 3.