Question

In: Statistics and Probability

You collect the following information on a sample of 100 adults: Y=LOTTERY= percentage of income the...

You collect the following information on a sample of 100 adults:

  • Y=LOTTERY= percentage of income the person spends on lottery tickets (in %)
  • EDUC= amount of education the individual has (in years)
  • AGE = age of the individual (in years),
  • CHILDREN = number of children the person has (in number of children)
  • INC1000= annual income of the individual (in 1,000s of dollars)

The data set can be found in Mod9-1Data. Run the multiple regression in Minitab. Assume a level of significance of 5%.

Lottery Educ Age Children Inc1000
5 15 50 2 41
7 10 26 0 22
0 13 40 3 24
10 9 46 2 20
5 14 40 3 32
5 15 39 2 42
3 8 36 3 18
0 16 44 1 47
0 20 47 4 85
6 10 52 1 23
0 18 51 2 61
0 17 41 2 70
12 9 42 2 22
7 12 53 1 27
11 9 72 1 25
2 16 38 2 43
11 12 41 5 34
2 14 50 3 53
7 9 41 3 20
0 16 52 0 71
10 9 41 2 16
8 10 45 3 19
1 16 58 0 64
11 11 53 0 25
7 14 61 2 31
3 17 30 1 42
5 17 40 0 50
9 11 73 3 31
5 15 43 4 35
10 9 49 3 18
7 10 50 0 26
10 10 27 1 23
1 17 46 3 39
4 14 47 1 22
7 14 47 3 31
8 12 28 1 29
8 14 26 1 29
3 17 32 2 30
5 16 42 5 21
3 11 53 1 26
0 17 46 1 66
8 14 33 3 29
3 16 52 0 48
8 11 58 3 20
0 18 28 3 80
7 10 53 2 31
7 14 43 1 26
0 16 49 2 36
7 9 38 1 26
9 10 44 0 21
8 9 32 1 24
0 12 44 3 18
7 10 52 0 28
0 16 40 2 42
8 11 53 6 21
7 8 43 2 28
8 17 23 0 27
8 12 21 0 34
7 9 50 3 28
9 12 46 1 30
5 7 82 0 23
0 20 45 3 95
0 11 23 0 22
11 9 40 3 27
8 12 36 3 23
0 10 42 1 29
9 7 36 0 25
7 14 58 3 25
0 16 36 0 28
8 9 37 2 25
6 10 53 2 27
7 17 42 2 39
0 19 50 4 63
8 11 33 0 28
8 11 27 3 29
0 16 30 2 34
7 11 40 2 19
6 13 32 2 22
8 11 69 2 17
0 17 24 0 34
1 17 32 2 44
6 8 21 0 28
0 19 31 2 53
10 11 53 1 16
9 14 43 1 22
5 14 39 1 27
0 7 37 2 22
10 8 57 1 23
10 10 31 1 24
13 8 71 0 11
6 15 59 3 50
7 15 33 3 37
3 11 33 3 24
0 11 41 3 30
5 12 53 3 21
0 16 35 1 53
0 17 54 0 31
10 9 55 2 29
6 16 24 0 36
11 12 56 3 27

null hypothesis for the test on the slope/coefficient on AGE-

alternative hypothesis=

computed test statistic=

table test statistic=

p-value=

statistical conclusion=

Predicted percentage of income spent of lottery tickets for a person with 12 years of education; 20 years old; 0 children; and an income of $25,000.=

null hypothesis for valid regression test=

alternative hypothesis for valid regression=

computed test statistic for the useful regression test=

table test statistic for the valid regression test=

p-value for the valid regression test=

statistical conclusion for the valid regression test=

Solutions

Expert Solution

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.658387462
R Square 0.43347405
Adjusted R Square 0.409620325
Standard Error 2.909780022
Observations 100
ANOVA
df SS MS F Significance F
Regression 4 615.442121 153.8605 18.17217 4.09443E-11
Residual 95 804.347879 8.46682
Total 99 1419.79
Coefficients Standard Error t Stat P-value
Intercept 11.90609377 1.785196734 6.669345 1.69E-09
Educ -0.430018471 0.132071926 -3.25594 0.001567
Age 0.029189885 0.025227671 1.157058 0.25015
Children 0.093435096 0.224313376 0.416538 0.677956
Inc1000 -0.074470531 0.027726044 -2.68594 0.008537

1. null hypothesis for the test on the slope/coefficient on AGE- H0: β2 = 0

2. alternative hypothesis= H1: β2 0

3. computed test statistic= 1.157

4. table test statistic (Using Excel function T.INV.2T(probability,n-2)) = T.INV.2T(0.05,98) = 1.984

5. p-value = 0.250

6. statistical conclusion = Since p-value is more than 0.05, we do not reject null hypothesis and conclude that β2 = 0.

7. Predicted percentage of income spent of lottery tickets for a person with 12 years of education; 20 years old; 0 children; and an income of $25,000.=

y = 11.906 - 0.43*Educ + 0.029*Age + 0.093*Children - 0.074*Inc100

= 11.906 - 0.43*12 + 0.029*20 + 0.093*0 - 0.074*25 = 5.467

8. null hypothesis for valid regression test= H0: β1 = β2 = β3 = β4 = 0

9. alternative hypothesis for valid regression= At least one βi 0

10. computed test statistic for the useful regression test= 18.172

11. table test statistic for the valid regression test (Using Excel function F.INV(probability,k-1,n-k)) = F.INV(0.05,4-1,100-4) = 0.117

12. p-value for the valid regression test= 0.000

13. statistical conclusion for the valid regression test= Since p-value is less than 0.05, we reject null hypothesis and conclude that at least one βi 0.


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