Question

In: Chemistry

Total volume of H2 produced, V= Partial Pressure of dry H2=

 

Determination of an Equivalent Mass by Electrolysis

Data

Identity of metal = Copper

Mass of metal anode = 11.167 g

Mass of anode after electrolysis = 10.930 g

Initial buret reading =50 mL

Buret reading after first electrolysis =49.2 mL

Buret reading after refilling = 50 mL

Buret reading after second electrolysis =47.2

Barometric pressure
(1 atm = 1013.25 mbar)

Temperature, T = 328 K


Vapor pressure of H2O at T=

Calculations (show work) Total volume of H2 produced, V=

Partial Pressure of dry H2=

(ignore any pressure effect due to liquid levels in buret)PH2= barometric pressure- PH2O

No. moles H2 produced, n=

Faradays passed (no. of moles of electrons)=

Loss in mass by anode=

Equivalent mass of metal=

mass lost/faradays passed

Molar mass of metal =

Charge, n, on cation=

Solutions

Expert Solution

Determination of an Equivalent Mass by Electrolysis

Data

Identity of metal      = Copper

Mass of metal anode    = 11.167 g

Mass of anode after electrolysis   = 10.930 g

Loss in mass by anode = 11.167 g - 10.930 g = 0.237 g

Initial burette reading    = 50 mL

Burette reading after first electrolysis = 49.2 mL

Buret reading after refilling = 50 mL

Buret reading after second electrolysis = 47.2

Total volume of H2 = (49.2 mL + 47.2 ml) = 96.4ml

Barometric pressure

(1 atm = 1013.25 mbar)

Temperature, T = 328 K

Vapor pressure of H2O at 328 K = 0.15546 atm

Partial Pressure of dry H2

PH2= barometric pressure- PH2O

PH2 1atm - 0.15546atm   = 0.84454 atm

No. moles H2 produced, n=

We can calculate number of moles H2 by using ideal gas equation

PV=nRT

R = 0.082 L atm K−1 mol−1

n = PV/RT

n= (0.84454atm x 0.0964L) /(0.082 L atm K−1 mol−1 x 328K) = 0.00303 moles

No. moles H2 produced, n= 0.00303 moles

Faradays passed (no. of moles of electrons)

1 mole H2 requires passage of 2 faradays

No. of faradays passed = .00303 moles x 2faradays/1mol H2 = 0.00606 faraday

Loss in mass by anode= 0.237 g

Equivalent mass of metal= mass lost/faradays passed

Equivalent mass of metal = 0.237 g/0.00606 = 39.1g/mol

Molar mass of metal = 2 x Equivalent mass = 2 x 39.1 =78.2 g/mol

Charge, n, on cation= 2

Molar mass of Cu is 63.546 g/mol . There is some error in experiment.


Related Solutions

A tank, containing O2 and H2, has a volume of 4.00 L and at total pressure...
A tank, containing O2 and H2, has a volume of 4.00 L and at total pressure is 24.44 atm. Calculate the mass of oxygen of which mole fraction is 0.4 in the tank at 25.0 °C .
On a cold, dry morning after a frost, the temperature was -5C and the partial pressure...
On a cold, dry morning after a frost, the temperature was -5C and the partial pressure of water in the atmosphere fell to 0.30 kPa. Will the frost sublime? What partial pressure of water would ensure that the frost remained?
If the total pressure is 1.07 atm, what is the partial pressure of Oxygen?
1.) Gas           Number of moles N2                    3.10 O2                    0.76 CO2                 0.12 If the total pressure is 1.07 atm, what is the partial pressure of Oxygen? (Your answer will be in atmospheres, but do NOT include units - Blackboard won't allow them. Use two decimal places, and simply give the number portion.) 2.) A reaction is carried out that produces hydrogen gas. The gas is collected in an inverted beaker over water at 25 oC. The vapor pressure of water at...
Derive the following statement "T(temperatue)-V(volume) and P(pressure)-V(volume) relationship in the adiabatic changes"
Derive the following statement "T(temperatue)-V(volume) and P(pressure)-V(volume) relationship in the adiabatic changes"
The pressure p and volume v of a given mass of gas are connected by the...
The pressure p and volume v of a given mass of gas are connected by the relation k=(p+a\v^2)(v-b) where a, b, and k are constants. Using the composite trapezoidal method, write a MatLab script to approximate the work done by the gas in expanding from an initial volume to a final volume. Express p in terms of v. Where W = Integral (Pdv)
What volume of H2 gas will be produced at 1.0 atm and 28 degrees Celsius if...
What volume of H2 gas will be produced at 1.0 atm and 28 degrees Celsius if 10g of Na are mixed with 100g of H2O.The other product of the reaction is NaOH
Calculate the volume of dry CO2 produced at body temperature (37 ∘C ) and 0.960 atm...
Calculate the volume of dry CO2 produced at body temperature (37 ∘C ) and 0.960 atm when 25.5 g of glucose is consumed in this reaction. V = L
The partial pressure of argon in the atmosphere is 7.10torr . Calculate the partial pressure in...
The partial pressure of argon in the atmosphere is 7.10torr . Calculate the partial pressure in mmHg and atm . Round each of your answers to 3 significant digits.
33. At a certain temperature and total pressure of 1.2 atm, the partial pressures of an...
33. At a certain temperature and total pressure of 1.2 atm, the partial pressures of an equilibrium mixture for 2A(g) → B(g) are PA = 0.60 atm and PB = 0.60 atm. After a disturbance, the system regains equilibrium with a total pressure of 1.6 atm. What is the partial pressure of A at the new equilibrium? atm
At a certain temperature and total pressure of 1.2 atm, the partial pressures of an equilibrium...
At a certain temperature and total pressure of 1.2 atm, the partial pressures of an equilibrium mixture for 2A(g) → B(g) are PA = 0.60 atm and PB = 0.60 atm. After a disturbance, the system regains equilibrium with a total pressure of 1.6 atm. What is the partial pressure of A at the new equilibrium?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT