In: Math
Suppose f is a function giving the altitude (height above
ground) in feet of a small plane, depending on time t in
seconds.
Select the best interpretation of each value, function, or
expression below.
(a) f(50)=1000 means
the altitude of the plane is 1000 feet after 50 secondsthe altitude of the plane is increasing at a rate of 50 feet per second after 1000 seconds the altitude of the plane is 50 feet after 1000 secondsthe altitude of the plane is increasing at a rate of 1000 feet per second after 50 seconds
(b) f'(1000)=50 means
the altitude of the plane is increasing at a rate of 50 feet per second after 1000 secondsthe altitude of the plane is 50 feet after 1000 seconds the altitude of the plane is 1000 feet after 50 secondsthe altitude of the plane is increasing at a rate of 1000 feet per second after 50 seconds
(c)
f(1000)−f(0) |
1000−0 |
= 50 means
the plane's speed increased an average of 50 feet per second over 1000 seconds the plane's altitude increased 50 feet per second for 1000 seconds the plane's altitude increased an average of 50 feet per second over 1000 seconds the plane's speed increased 50 feet per second for 1000 seconds
(d)
1 |
1000 |
1000 | f(t)dt |
0 |
is the plane's
average altitude over 1000 seconds, in feetinstantaneous rate of change in altitude after 1000 seconds, in feet per second average rate of change in altitude over 1000 seconds, in feet per second
(e)
d |
dx |
x | f(t)dt |
0 |
is the plane's
average altitude function, in feetaverage speed function, in feet per second instantaneous rate of change in altitude, in feet per secondaverage velocity function, in feet per second
(f)
1000 | f'(t)dt |
0 |
= 50 means
the net change in the speed of the plane over 1000 seconds is 50 feet per secondthe average change in the speed of the plane over 1000 seconds is 50 feet per second the average change in the altitude of the plane over 1000 seconds is 50 feet the net change in the altitude of the plane over 1000 seconds is 50 feetthe instantaneous change in the altitude of the plane at 1000 seconds is 50 feetthe instantaneous change in the speed of the plane at 1000 seconds is 50 feet per second
(a) f(50)=1000 means
the altitude of the plane is 1000 feet after 50 seconds
(b) f'(1000)=50 means
the altitude of the plane is increasing at a rate of 50 feet per second after 1000 seconds
(c)
f(1000)−f(0) |
1000−0 |
= 50 means
the plane's altitude increased an average of 50 feet per second over 1000 seconds
(d)
1 |
1000 |
1000 | f(t)dt |
0 |
is the plane's average altitude over 1000 seconds, in feet
(e)
d |
dx |
x | f(t)dt |
0 |
is the plane's average altitude function
(f)
1000 | f'(t)dt |
0 |
= 50 means
the net change in the altitude of the plane over 1000 seconds is 50 feet