In: Statistics and Probability
Find the chi-square value X2/L corresponding to a sample size of 4 and a confidence level of 98 percent. Round to three decimal places.
Solution:
n = 4
At 98% confidence level the
is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02 / 2 = 0.01
/2,df =
0.01,3 = 11.345
and
1-
/2,df =
0.99,3 = 0.115
2L
=
2
/2,df
= 11.345
2R
=
21 -
/2,df = 0.115