In: Finance
•Burnout Batteries
•Initial Cost = $36 each
•3-year life
•$100 per year to keep charged
•Expected salvage = $5
•Straight-line depreciation
•Long-lasting Batteries
•Initial Cost = $60 each
•5-year life
•$88 per year to keep charged
•Expected salvage = $5
•Straight-line depreciation
The machine chosen will be replaced indefinitely and neither machine will have a differential impact on revenue. No change in NWC is required.
The required return is 15%, and the tax rate is 34%.
Which battery should be chosen?
Burnout batteries(Mach.A) | Long last. batt.(Mach.B) | |
Initial Cost Life Keep up charges Expected salvage value Dep method , SL dep. |
$36 each 3 yr $100 $5 ($36-$5)/3 = $ 10.33 |
$60each 5 yr $88 $5 ($60-$5)/5 = $ 11 |
Mach.A(burnout) | Mach.B(longlife) | |
Initial cost plus keep up charges Dep. Total cost Running cost of mach per year Cumulative PV factor for mach.A for 1-3 yrs @15%* Cumulative PV factor for mach.A for 1-5 yrs @15%* PV of Running cost of mach's(1) PV of Salvage value at the year end(2) Total PV of Running cost of mach's(1+2) Equivalent annual PV of Cash outflows |
$136 $10.33 $146.33 (146.33/3) =$48.77 2.2825 $111.317 $3.28 $114.597 114.597/2.2825 = $50.206 |
$148 $11 $159 (159/5) =$31.8 3.35197 $106.59 $5*.4977=$2.48 $109.07 109.07/3.35197 =$35.53 |
Battery with long ife should be chosen as it has lower cash outflows as compared to the burnout one.
* For calculating PV factor = 1/(1+r)^n
where r= rate of return
n = time period
Note that *
PV of Salvage value of Mach.A will be at the end of 3yrs, and of Mach.B will be at the end of 5 years
* Also sorry for diff. spacing in table!! Hope you understand.