Question

In: Finance

•Burnout Batteries •Initial Cost = $36 each •3-year life •$100 per year to keep charged •Expected...

•Burnout Batteries

•Initial Cost = $36 each

•3-year life

•$100 per year to keep charged

•Expected salvage = $5

•Straight-line depreciation

•Long-lasting Batteries

•Initial Cost = $60 each

•5-year life

•$88 per year to keep charged

•Expected salvage = $5

•Straight-line depreciation

The machine chosen will be replaced indefinitely and neither machine will have a differential impact on revenue. No change in NWC is required.

The required return is 15%, and the tax rate is 34%.

Which battery should be chosen?

Solutions

Expert Solution

Burnout batteries(Mach.A) Long last. batt.(Mach.B)

Initial Cost

Life

Keep up charges

Expected salvage value

Dep method , SL dep.

$36 each

3 yr

$100

$5

($36-$5)/3 = $ 10.33

$60each

5 yr

$88

$5

($60-$5)/5 = $ 11

Mach.A(burnout) Mach.B(longlife)

Initial cost plus keep up charges

Dep.

Total cost

Running cost of mach per year

Cumulative PV factor for mach.A for 1-3 yrs @15%*

Cumulative PV factor for mach.A for 1-5 yrs @15%*

PV of Running cost of mach's(1)

PV of Salvage value at the year end(2)

Total PV of Running cost of mach's(1+2)

Equivalent annual PV of Cash outflows

$136

$10.33

$146.33

(146.33/3)

=$48.77

2.2825

$111.317

$3.28

$114.597

114.597/2.2825 = $50.206

$148

$11

$159

(159/5)

=$31.8

3.35197

$106.59

$5*.4977=$2.48

$109.07

109.07/3.35197

=$35.53

Battery with long ife should be chosen as it has lower cash outflows as compared to the burnout one.

* For calculating PV factor = 1/(1+r)^n

where r= rate of return

n = time period

Note that *

PV of Salvage value of Mach.A will be at the end of 3yrs, and of Mach.B will be at the end of 5 years

* Also sorry for diff. spacing in table!! Hope you understand.


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