In: Statistics and Probability
You wish to determine if there is a negative linear correlation
between the two variables at a significance level of α=0.01α=0.01.
You have the following bivariate data set.
| x | y |
|---|---|
| 67.2 | 118 |
| 53.8 | 131.4 |
| 68.2 | 321.5 |
| 60.5 | -67.4 |
| 58.2 | 154.3 |
| 60.5 | 230.3 |
| 41.2 | 157.7 |
| 105.5 | 91 |
| 72.8 | -80 |
| 80.9 | -105.7 |
| 79.6 | 125.1 |
| 81.7 | -58.5 |
| 67.5 | 70.3 |
| 48.5 | -81 |
| 17.9 | 184.8 |
| 57.4 | 149.2 |
| 59 | 30.8 |
| 43.1 | 104.9 |
| 63.9 | -75 |
| 81.4 | -1.2 |
| 50.5 | -58.2 |
| 90.9 | -27.9 |
| 77 | 115.3 |
| 54.2 | 171.7 |
| 78.9 | 208.3 |
| 54.3 | -6.6 |
| 37.6 | 116.5 |
| 33 | 113.7 |
| 75.9 | 61.9 |
| 108.2 | -54.3 |
| 54.4 | 81.2 |
| 87.3 | 279.8 |
| 68 | -68.2 |
| 61.1 | 143.4 |
| 78 | 137.5 |
| 82.1 | 184.1 |
| 43.5 | 439.4 |
| 82 | 16.3 |
| 89.4 | 226.7 |
| 94.7 | 166.1 |
What is the correlation coefficient for this data set?
r =
To find the p-value for a correlation coefficient, you need to
convert to a t-score:
t=√r2(n−2)1−r2t=r2(n-2)1-r2
This t-score is from a t-distribution with
n–2 degrees of freedom.
What is the p-value for this correlation coefficient?
p-value =
Your final conclusion is that...
Note: In your calculations, round both r and t to 3 decimal places
in ALL calculations.