In: Math
A hamburger joint took in $634.70 and sold (a combination of hamburgers and cheeseburgers) for a total of 650 burgers. Hamburgers cost $.89 and cheeseburgers cost $1.09. How many of each were sold?
Answer: Number of
Hamburgers=369 and number of
Cheeseburgers=281.
Explanation: Let the number of Hamburgers sold
were 'x' and number of Cheeseburgers sold were 'y'.
So, according to the question, total number of burgers sold were=650. So,
--------------------------------------------- (1)
Now, according to the question, the Hamburger cost=$0.89 and Cheeseburger cost=$1.09 and total cost=$634.70. So,
------------------------------------------ (2)
Substituting x=650-y from eqn 1 into eqn 2,
--------------------------------------------------- (3)
Now, substituting y=281 into eqn 1,
---------------------------------------------------- (4)
Hence, number of Hamburgers were 369 and number of Cheeseburgers were 281.