A hamburger joint took in $634.70 and sold (a combination of hamburgers and cheeseburgers) for a...

A hamburger joint took in $634.70 and sold (a combination of hamburgers and cheeseburgers) for a total of 650 burgers. Hamburgers cost $.89 and cheeseburgers cost $1.09. How many of each were sold?

Solutions

Expert Solution

Answer: Number of Hamburgers=369 and number of Cheeseburgers=281.
Explanation: Let the number of Hamburgers sold were 'x' and number of Cheeseburgers sold were 'y'.

So, according to the question, total number of burgers sold were=650. So,

--------------------------------------------- (1)

Now, according to the question, the Hamburger cost=$0.89 and Cheeseburger cost=$1.09 and total cost=$634.70. So,

------------------------------------------ (2)

Substituting x=650-y from eqn 1 into eqn 2,

--------------------------------------------------- (3)

Now, substituting y=281 into eqn 1,

---------------------------------------------------- (4)

Hence, number of Hamburgers were 369 and number of Cheeseburgers were 281.

milcah answered 1 year ago

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