? ′′ − 8? ′ − 20? = xe^(x) initial condition is ?(0) = 0 y'(0)=0....

? ′′ − 8? ′ − 20? = xe^(x) initial condition is ?(0) = 0 y'(0)=0. laplace/inverse/partialfract. show all work please!

Expert Solution

milcah answered 2 years ago

y′ -xe^x = 0 , y(0) = 4 using laplace transforms

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