In: Statistics and Probability
A population of values has a normal distribution with μ = 118.4 μ = 118.4 and σ = 87.7 σ = 87.7 . You intend to draw a random sample of size n = 24 n = 24 .
Find the probability that a single randomly selected value is less than 62.9. P(X < 62.9) = ______
Find the probability that a sample of size n = 24 n = 24 is randomly selected with a mean less than 62.9. P(M < 62.9) = ______
Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Solution :
Given that ,
a) P(x < 62.9)
= P[(x - ) / < (62.9 - 118.4) / 87.7 ]
= P(z < -0.633 )
Using z table,
= 0.2634
b) = 118.4
= / n = 87.7 / 24 = 17.902
P(M < 62.9) = P((M - ) / < (62.9 - 118.4) /17.902 )
= P(z < -3.100)
Using z table
= 0.0010