In: Statistics and Probability
A new car that is a gas- and electric-powered hybrid has recently hit the market. The distance traveled on 1 gallon of fuel is normally distributed with a mean of 45 miles and a standard deviation of 7 miles. Find the probability of the following events:
A. The car travels more than 53 miles per gallon.
Probability =
B. The car travels less than 42 miles per gallon.
Probability =
C. The car travels between 39 and 52 miles per gallon.
Probability =
Solution :
Given ,
mean =
= 45
standard deviation =
= 7
P(x > 53) = 1 - P(x< 53)
= 1 - P[(x -)
/
< (53 -45) /7 ]
= 1 - P(z <1.14 )
Using z table
= 1 - 0.8729
= 0.1271
probability=0.1271
(b)
P(X< 42 ) = P[(X-
) /
< ( 42 -45) /7 ]
= P(z <-0.43 )
Using z table
= 0.3336
probability=0.3336
(c)
P(39< x <52 ) = P[(39 -45) /7 < (x -
) /
< (52-45) /7 )]
= P( -0.86< Z <1 )
= P(Z < 1) - P(Z < -0.86)
Using z table
= 0.8413-0.1949
probability= 0.6464