explain why tetradentate or hexadentate ligands are more
satisfactory as titrants in EDTA titrations than unidentate...
explain why tetradentate or hexadentate ligands are more
satisfactory as titrants in EDTA titrations than unidentate
ligands
Solutions
Expert Solution
Multidentate ligands like EDTA have more electron pairs
available and thus they form more bonds. They form Chelate complex
with Transition Metals.
Multidentate ligands tend to form 1:1 complexes producing a
clear end point.
1:1 Complexes formed with EDTA, for example, have a very simple
formation constant.
For the following reaction :
M + EDTA ->(equilibrium) M.EDTA
The formation constant for above reaction
Kf= [M.EDTA]/[M][EDTA]
which is simple, as compared to reactions where a unidentate ligand
reacts with a metal ,
M + nL --> MLn
Kf for this reaction is more complex than the one we
obtained above.
Therefore, We can conclude that EDTA or simply any multi-dentate
ligand simplifies the equilibrium equation.
For multi-dentate ligands, the overall interaction between the
central metal atom and the ligands is very strong as compared to
single interaction.
Explain in DETAILS how do EDTA displacement titration and
indirect edta titrations work and the steps to do the calculation
for it (How to exactly find the moles of the ion in the sample.
Show an example and use numbers to show the calculations.
More than 40 percent of information technology (IT) projects do
not produce a satisfactory outcome. The average company spends more
than $1 million a year for these unsatisfactory outcomes. An
estimated ten percent of a typical organization’s IT staff worked
on projects that have no business value. What controls will need to
be initiated as an accountant to resolve these issues?
Why are aldehydes usually more reactive than ketones? Why are
ketones more reactive than esters, and ester more reactive than
amides? Please help explain with the help of steric, indcutive and
resonance effects. Show an example for each class of compounds
please. Thank you!
1. What is the spectrochemical series? Explain why cyano or
phosphine ligands are placed high in the spectrochemical series but
the hydroxide ligand or the halo ligands are quite low in the
spectrochemical series?
2. what are the possible geometries for the six coordinate
nickel (II) complexes in this experiment? Draw simple d-orbital
ligand field energy diagrams to show the possibilities.