In: Finance
You would like to practice your knowledge of
investment and quantitative methods for
finance that you learnt at Oxford, so you found two call options A
and B, both options sell in the market for $5, for an underlying
stock which currently sells at $30. Both options mature in one
year, and the risk free rate is 6% and a variance of 30%. Upon
maturity, you can exercise
option A for $25, and option B for $35.
Which option you choose to buy? Explain your answer with
details
Std dev = variance^(1/2) = 30^(1/2) = 5.477
Call A
As per Black Scholes Model | |||
Value of call option = (S)*N(d1)-N(d2)*K*e^(-r*t) | |||
Where | |||
S = Current price = | 30 | ||
t = time to expiry = | 1 | ||
K = Strike price = | 25 | ||
r = Risk free rate = | 6.0% | ||
q = Dividend Yield = | 0% | ||
σ = Std dev = | 5.477% | ||
d1 = (ln(S/K)+(r-q+σ^2/2)*t)/(σ*t^(1/2) | |||
d1 = (ln(30/25)+(0.06-0+0.05477^2/2)*1)/(0.05477*1^(1/2)) | |||
d1 = 4.451733 | |||
d2 = d1-σ*t^(1/2) | |||
d2 =4.451733-0.05477*1^(1/2) | |||
d2 = 4.396963 | |||
N(d1) = Cumulative standard normal dist. of d1 | |||
N(d1) =0.999996 | |||
N(d2) = Cumulative standard normal dist. of d2 | |||
N(d2) =0.999995 | |||
Value of call= 30*0.999996-0.999995*25*e^(-0.06*1) | |||
Value of call= 6.46 |
Call B
As per Black Scholes Model | |||
Value of call option = (S)*N(d1)-N(d2)*K*e^(-r*t) | |||
Where | |||
S = Current price = | 30 | ||
t = time to expiry = | 1 | ||
K = Strike price = | 35 | ||
r = Risk free rate = | 6.0% | ||
q = Dividend Yield = | 0% | ||
σ = Std dev = | 5.477% | ||
d1 = (ln(S/K)+(r-q+σ^2/2)*t)/(σ*t^(1/2) | |||
d1 = (ln(30/35)+(0.06-0+0.05477^2/2)*1)/(0.05477*1^(1/2)) | |||
d1 = -1.691634 | |||
d2 = d1-σ*t^(1/2) | |||
d2 =-1.691634-0.05477*1^(1/2) | |||
d2 = -1.746404 | |||
N(d1) = Cumulative standard normal dist. of d1 | |||
N(d1) =0.045358 | |||
N(d2) = Cumulative standard normal dist. of d2 | |||
N(d2) =0.04037 | |||
Value of call= 30*0.045358-0.04037*35*e^(-0.06*1) | |||
Value of call= 0.03 |
Buy Call A as it has higher intrinsic value than B