In: Chemistry
For the reaction
3NO2(g)+H2O(l)→2HNO3(aq)+NO(g),
What is the mass of HNO3 that is produced when 24.45 g of NO2 and
24.45 g of H2O react
number of moles = weight of substance / molar mass of substance
number of moles of NO2 = 24.45g / 46 g/mol = 0.5315 moles
number of moles of H2O = 24.45g / 18g/mol = 1.358 moles
limiting reagent is the NO2
From the reaction,
3 moles of NO2 produces 2 moles of HNO3
then 0.5315 moles of NO2 produces (2 * 0.5315) / 3 = 0.3543 moles
therefore mass of HNO3 produced = number of moles * molar mass
= 0.3543mol * 63.01g/mol
= 22.326 grams