Question

In: Statistics and Probability

In recent years, a growing array of entertainment options competes for consumer time. By 2004, cable...

  1. In recent years, a growing array of entertainment options competes for consumer time. By 2004, cable television and radio surpassed broadcast television, recorded music, and the daily newspaper to become the two entertainment media with the greatest usage (The Wall Street Journal, January 26, 2004). Researchers used a sample of 15 individuals and collected data on the hours per week spent watching cable television and hours per week spent listening to the radio.

    Individual     Television          Radio

           1                      22                    25

2                      8                      10

3                      25                    29

4                      22                    19

5                      12                    13

6                      26                    28

7                      22                    23

8                      19                    21

9                      21                    21

10                    23                    23

11                    14                    15

12                    14                    18

13                    14                    17

14                    16                    15

15                    24                    23

  1. Use a .05 level of significance and test for a difference between the population mean usage for cable television and radio. What is the p-value? (You must state H0and Ha, and compute the test statistic.)
  2. Provide a 95% confidence interval estimate of the difference between the population mean usage for cable television and radio.

Solutions

Expert Solution

Result:

  1. In recent years, a growing array of entertainment options competes for consumer time. By 2004, cable television and radio surpassed broadcast television, recorded music, and the daily newspaper to become the two entertainment media with the greatest usage (The Wall Street Journal, January 26, 2004). Researchers used a sample of 15 individuals and collected data on the hours per week spent watching cable television and hours per week spent listening to the radio.

Individual

Television

Radio

difference

1

22

25

-3

2

8

10

-2

3

25

29

-4

4

22

19

3

5

12

13

-1

6

26

28

-2

7

22

23

-1

8

19

21

-2

9

21

21

0

10

23

23

0

11

14

15

-1

12

14

18

-4

13

14

17

-3

14

16

15

1

15

24

23

1

  1. Use a .05 level of significance and test for a difference between the population mean usage for cable television and radio. What is the p-value? (You must state H0and Ha, and compute the test statistic.)

Difference d = television - radio

Ho: µd=0 H1: µd ≠ 0

= mean of difference( x1-x2)

Paired t Test

Data

Hypothesized Mean Difference

0

Level of significance

0.05

Intermediate Calculations

Sample Size

15

DBar

-1.2000

Degrees of Freedom

14

SD

1.9712

Standard Error

0.5090

t Test Statistic

-2.3577

Two-Tail Test

Lower Critical Value

-2.1448

Upper Critical Value

2.1448

p-Value

0.0335

Reject the null hypothesis

Test statistic t = -2.3577

P value =0.0335

since p value 0.0335 is < 0.05 level of significance, Ho is rejected.

we conclude that there is a significant difference between the population mean usage for cable television and radio.

  1. Provide a 95% confidence interval estimate of the difference between the population mean usage for cable television and radio.

Confidence Interval Estimate for the Mean

Data

Sample Standard Deviation

1.9712

Sample Mean

-1.2

Sample Size

15

Confidence Level

95%

Intermediate Calculations

Standard Error of the Mean

0.5090

Degrees of Freedom

14

t Value

2.1448

Interval Half Width

1.0916

Confidence Interval

Interval Lower Limit

-2.2916

Interval Upper Limit

-0.1084

95% confidence interval estimate of the difference = (-2.2916, -0.1084)


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