In: Statistics and Probability
A sample of n = 16 scores is obtained from a population with µ = 50 and σ = 16. If the sample mean is M = 58, then what is the z-score for the sample mean?
z = - 2.00 |
||
z = +0.50 |
||
z = +2.00 |
||
z = +8.00 |
A researcher selects a random score from a normally distributed population. What is the probability that the score will be greater than z = +1.5 and less than z = -1.5?
.07 |
||
.13 |
||
.43 |
||
.86
|
Finn receives a final exam score of 65. The class had a mean of 75 and standard deviation of 10. What percent of students in Finn's class scored lower than him?
84% |
||
50% |
||
34% |
||
16% |
A normal distribution has μ = 80 and σ = 10. What is the probability of randomly selecting a score greater than 95 from this distribution?
p = 0.9332 |
||
p = 0.1587 |
||
p = 0.4332 |
||
p = 0.0668 |
Solution:
1)
z-score for the sample mean
= [M - ]/[/n]
= [58 - 50]/[16/16]
= +2.00
z = +2.00
2)
P(Z < -1.5 OR Z > 1.5)
= 1 - { P(Between -1.5 AND 1.5) }
= 1 - { P(Z < 1.5) - P(Z < -1.5) }
= 1 - { 0.9332 - 0.0668 }
= 0.13
Answer : 0.13
3)
Given, X follows Normal distribution with,
= 75
= 10
Find P(X < 65)
= P[(X - )/ < (65 - )/]
= P[Z < (65 - 75)/10]
= P[Z < -1.00]
= 0.1587 ... ( use z table)
= 15.87%
= 16%
Answer : 16%
4)
Given, X follows Normal distribution with,
= 80
= 10
P(X > 95)
= P[(X - )/ > (95 - )/]
= P[Z > (95 - 80)/10]
= P[Z > 1.50]
= 1 - P[Z < 1.50]
= 1 - 0.9332 ..( use z table)
= 0.0668
Answer : 0.0668