In: Operations Management
Chemco produces two chemicals A and B. These chemicals are produced via two manufacturing processes. Process 1 requires 2 hours of labor and 1 lb of raw materials to produce 2 oz of A and 1 oz of B. Process 2 requires 3 hours of labor and 2 lbs of raw material to produce 3 oz of A and 2 oz of B. Sixty hours of labor and 40 lbs of raw material are available. Demand for Chemical A is unlimited, but only 20 oz of B can be sold. Chemical A sells for $16/oz, and B sells for $14/oz. Any chemical B that is unsold must be disposed of at a cost of $2/oz. Formulate an LP model to maximize Chemicos revenue and solve.
1. Maximum Revenue
2. Amount of chemical A produced (oz)
3. Amount of chemical B produced and sold (oz)
4. Amunt of chemical B destroyed (oz)
Solution:-
Consider Variable as:-
X1 = Process 1
X2 = Process 2
A = Chemical A produced
B = Chemical B produced
B2 = Chemical unsold
Now,
To maximize chemicos revenue,
Z= ( Cost of A) (Units of process 1) + (cost of B) ( units of process 2)- (cost of B2)(units of B unsold)
Z = 16 (2x1 + 3x2) + 14 (x1 + 2x2 - B2) - 2B2
Maximize are at the Z value
Z = 16 (2x1 + 3x2) + 14 (x1 + 2x2 - B2) - 2B2
Let the equation are:-
Constraint 1:- At most, 60 hours of labor are available
[( hour of labor) (Units of chemical produced by process 1) + (hour of labor) (Units of a chemical produced by process 2)]
= 2x1 + 3x2
Constraint 2:- At most, 40 lbs of raw materials are available
[(pounds of raw materials ) (Units of a chemical produced by
process 1) + (pounds of materials) (Units of a chemical produced by
process 2)]
= x1 + 2x2
Constraint 3:- At most, 20 ounces of chemical B can be sold.
[(ounces of a chemical produced by process 1) + (ounces of a chemical produced by process 2) - (ounces of a chemical unsold)]
x1 + 2x2 - B2
Thus, the formulation of linear programme model is shown as
Maximize Z = 16 (2x1 + 3x2) + 14 (x1 + 2x2 - B2) - 2B2
Z= 32x1 + 48x2 + 14x1 + 28x2 - 14 B2 - 2B2
Mamimize Z= 46x1 + 76x2 - 16B2
Depending on the constraint
2x1 + 3x2
x1 + 2x2
x1 + 2x2 - B2
Thus all variables x1, x2, B2 are