The following cell reaction furnishes 0.62V. 2Fe3+(aq) + Sn2+(aq) ---> 2 Fe2+(aq) + Sn4+(aq) The maximum...

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Expert Solution

Eocell = 0.62 V

decrease in free energy = maximum electrical energy

- DG = work (or) energy = n F Eocell

n = number of electrons transfered = 2

F = faraday = 9.65 x 10⁴ C

work (or) energy = n F Eocell

= 2 x9.65 x 10⁴ x 0.62

= 119660 J

= 1.197 x 10^5 J

from the balanced equation: 2 mole Fe (III) ion ---------------> 1.197 x 10^5 J

1 mole Fe(III) ion ------------> 1.197 x 10^5 J / 2 mole

----------------> 5.98 x 10^4 J / mole

answer : (D) 5.98 x 10⁴ J/mole Fe(III) ion

note check your answer once . it is 10^4 not 10^5 . so the answer should be D)

queen_honey_blossom answered 1 year ago

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