Question
In: Chemistry
The following cell reaction furnishes 0.62V. 2Fe3+(aq) + Sn2+(aq) ---> 2 Fe2+(aq) + Sn4+(aq) The maximum...
The following cell reaction furnishes 0.62V.
2Fe3+(aq) + Sn2+(aq) ---> 2 Fe2+(aq) + Sn4+(aq)
The maximum electrical energy per mole of Fe(III) ion is (1F = 9.65 x 104 C)
(A) 1.197 x 105 J/mole Fe(III) ion
(B) 2.394 x 105 J/mole Fe(III) ion
(C) 5.98 x 105 J/mole Fe(III) ion
(D) 5.98 x 104 J/mole Fe(III) ion
Correct answer is (C). Please explain why, thank you.
Solutions
Expert Solution
Eocell = 0.62 V
decrease in free energy = maximum electrical energy
- DG = work (or) energy = n F Eocell
n = number of electrons transfered = 2
F = faraday = 9.65 x 104 C
work (or) energy = n F Eocell
= 2 x9.65 x 104 x 0.62
= 119660 J
= 1.197 x 10^5 J
from the balanced equation: 2 mole Fe (III) ion ---------------> 1.197 x 10^5 J
1 mole Fe(III) ion ------------> 1.197 x 10^5 J / 2 mole
----------------> 5.98 x 10^4 J / mole
answer : (D) 5.98 x 104 J/mole Fe(III) ion
note check your answer once . it is 10^4 not 10^5 . so the answer should be D)
queen_honey_blossom answered 2 years agoRelated Solutions
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