In: Statistics and Probability
How much money does the average professional football fan spend on food at a single football game? That question was posed to 45 randomly selected football fans. The sample results provided a sample mean and standard deviation of $16.00 and $2.50, respectively. Use this information to construct a 95% confidence interval for the mean. The Confidence Interval was: 16.00±____*2.5045?
Degrees of freedom = n - 1 = 45 - 1 = 44
For 44 degrees of freedom and 95% confidence interval:
Critical t value = 2.015
Hence,
95% confidence interval will be:
(15.25, 16.75)