In: Statistics and Probability
A Washington, D.C., “think tank” announces the typical teenager sent 67 text messages per day in 2017. To update that estimate, you phone a sample of 12 teenagers and ask them how many text messages they sent the previous day. Their responses were:
51 | 175 | 47 | 49 | 44 | 54 | 145 | 203 | 21 | 59 | 42 | 100 |
State the null hypothesis and the alternate hypothesis.
State the decision rule for 0.05 significance level. (Round your answer to 3 decimal places.)
Reject H0 if t > ______
Compute the value of the test statistic. (Round your answer to 3 decimal places.)
value of the test statistic:
At the 0.05 level, can you conclude that the mean number is greater than 67?
(reject or do not reject) H0. and conclude that the mean number of text messages is (less than 67 or greater than 67)
Estimate the p-value.
possible answers:
1) less than 0.10
2) between 0.005 and 0.10
3) between 0.0005 and 0.005
4) between 0.005 and 0.01
5) between 0.01 and 0.025
6) between 0.025 and 0.05
7) greater than 0.05
Reject H0 if t > 1.796
value of the test statistic: 0.903
At the 0.05 level, can you conclude that the mean number is greater than 67?
(do not reject) H0. and conclude that the mean number of text messages is (less than 67 )
Estimate the p-value.
7) greater than 0.05