In: Statistics and Probability
Suppose that two different sets of treatments are of interest.
The first
treatment has two levels ( A versus B ). The second treatment has
two levels ( a
versus b ). Denote by y the response variable of interest.
a) Construct a statistical test for testing whether there is a
difference in expected
value of y between A and B.
b) Construct a statistical test for testing whether there is a
difference in expected
value of y among the four treatment combinations Aa, Ab, Ba,
Bb.
(a)
Construct a statistical test for testing whether there is a
difference in expected
value of y between A and B.
Two Independent Samples t test
H0: Null Hypothesis: ( There is no significant difference in expected value of y between A and B. )
HA: Alternative Hypothesis: ( There is a significant difference in expected value of y between A and B. ) (Claim)
Procedure:
From the given data, obtain the Test Statistic as follows:
where sP is the pooled standard deviation.
From the given significace level and degrees of freedom nA + nB - 2, get the calculate of critical values of t.
If the calculated value of t is less than critical value of t, the difference is not significant. Fail to reject null hypothesis.
Conclusion:
The data do not support the claim that there is a significant
difference in expected value of y between A and B.
If the calculated value of t is greater than critical value of t, the difference is significant. Reject null hypothesis.
Conclusion:
The data do support the claim that there is a significant
difference in expected value of y between A and B.
(b)
Construct a statistical test for testing whether there is a difference in expected value of y among the four treatment combinations Aa, Ab, Ba, Bb.
One way ANOVA test
H0: Null Hypothesis: (There is no difference in expected value of y among the four treatment combinations Aa, Ab, Ba, Bb. )
HA: Alternative Hypothesis: (There is a difference in expected value of y among the four treatment combinations Aa, Ab, Ba, Bb. ) (Claim)
Procedure:
From the given data, complete the ANOVA Table:
Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F |
Treatments | SST | k-1 | ||
Error | SSE | N - k | ||
Total | SS | N - 1 |
From the given value of significance level = and degrees of freedom for numerator and denominaor, get the value of critical value of F.
If the calculated value of F is less than critical value of F, the difference is not significant. Fail to reject null hypothesis.
Conclusion:
The data do not support theclaim that there is a difference in
expected value of y among the four treatment combinations Aa, Ab,
Ba, Bb.
If the calculated value of F is greater than critical value of F, the difference is significant. Reject null hypothesis.
Conclusion:
The data support theclaim that there is a difference in expected
value of y among the four treatment combinations Aa, Ab, Ba,
Bb.