Question

In: Statistics and Probability

Suppose that two different sets of treatments are of interest. The first treatment has two levels...

Suppose that two different sets of treatments are of interest. The first
treatment has two levels ( A versus B ). The second treatment has two levels ( a
versus b ). Denote by y the response variable of interest.
a) Construct a statistical test for testing whether there is a difference in expected
value of y between A and B.
b) Construct a statistical test for testing whether there is a difference in expected
value of y among the four treatment combinations Aa, Ab, Ba, Bb.

Solutions

Expert Solution

(a)

Construct a statistical test for testing whether there is a difference in expected
value of y between A and B.

Two Independent Samples t test

H0: Null Hypothesis: ( There is no significant difference in expected value of y between A and B. )

HA: Alternative Hypothesis: ( There is a significant difference in expected value of y between A and B. ) (Claim)

Procedure:
From the given data, obtain the Test Statistic as follows:

where sP is the pooled standard deviation.

From the given significace level and degrees of freedom nA + nB - 2, get the calculate of critical values of t.

If the calculated value of t is less than critical value of t, the difference is not significant. Fail to reject null hypothesis.

Conclusion:
The data do not support the claim that there is a significant difference in expected value of y between A and B.

If the calculated value of t is greater than critical value of t, the difference is significant. Reject null hypothesis.

Conclusion:
The data do support the claim that there is a significant difference in expected value of y between A and B.

(b)

Construct a statistical test for testing whether there is a difference in expected value of y among the four treatment combinations Aa, Ab, Ba, Bb.

One way ANOVA test

H0: Null Hypothesis: (There is no difference in expected value of y among the four treatment combinations Aa, Ab, Ba, Bb. )

HA: Alternative Hypothesis: (There is a difference in expected value of y among the four treatment combinations Aa, Ab, Ba, Bb. ) (Claim)

Procedure:
From the given data, complete the ANOVA Table:

Source of Variation Sum of Squares Degrees of Freedom Mean Square F
Treatments SST k-1
Error SSE N - k
Total SS N - 1

From the given value of significance level = and degrees of freedom for numerator and denominaor, get the value of critical value of F.

If the calculated value of F is less than critical value of F, the difference is not significant. Fail to reject null hypothesis.

Conclusion:
The data do not support theclaim that there is a difference in expected value of y among the four treatment combinations Aa, Ab, Ba, Bb.

If the calculated value of F is greater than critical value of F, the difference is significant. Reject null hypothesis.

Conclusion:
The data support theclaim that there is a difference in expected value of y among the four treatment combinations Aa, Ab, Ba, Bb.


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