Question

Bivariate Data Analysis (Chi-Square Analysis)

• Frequency Table

	18-	18+	Row Total
Comedy	27	43	70
	27.84%	43.00%	35.53%
	34.47	35.53
Drama & Romance	70	57	127
	72.16%	57.00%	64.47%
	62.53	64.47
Column Total	97	100	197
	49.24%	50.76%	100.00%

Cell contents:

    Observed frequency

    Percentage of column

    Expected frequency

• Tests of Independence

Test	Statistic	Df	P-Value
Chi-Square	4.943	1	0.0262

Insert tests of independence.

Conduct the 4 -step chi square independence test (or chi

- square homogeneity test)

Verify the assumption of chi-square analysis.

please help guys... im so stressed! Thank you in advance.

Answer 1

Assumptions of chi square test:

1. Both the variables are nominal.

2. The data in each cells are frequencies or counts of cases.

3. The categories of variables that is comedy and drama romance are mutually exclusive , and the categories 18- and 18+ are mutually exclusive.

4. The value of each cell is more than 5.

Thus since all the assumptions are satisfied, we can use chi square test of Independence.

Step 1,

Null hypothesis:

Ho: The row variable and the column variable are independent.

Alternative hypothesis:

H1: Thee row variable and the column variable are not independent.

Conclusion: Thus there is sufficient evidence to conclude that the row variable and column variable are not independent.