In: Statistics and Probability
Which one is the correct characteristics of t distribution with 10 degrees of freedom? Choose all applied.
a. |
symmetric around 0 |
|
b. |
mean is 10 |
|
c. |
it is taller than t distribution with 5 degrees of freedom. |
|
d. |
variance is 10/8 |
If weight of products ~ N(120LB, 30LB) then what is chance that
weight of product is larger than 130 LB?
Provide an answer with 3 decimal points
For t with 50 degrees of freedom, what is the 99th percentile of value of t ?
Provide an answer with 3 decimal points
For t with 50 degrees of freedom, what is the chance that
t has a value larger than 1.2?
Provide an answer with 3 decimal points
f weight of products ~ N(120LB, 30LB) then what is the 95th percentile of
the weight of product?
Provide an answer with 2 decimal points
For t with 50 degrees of freedom, what is the chance that
t has a value between -1.5 and -0.5?
Provide an answer with 3 decimal points
If the weight of products ~ N(120LB, 30LB) then what is chance that
the weight of product is between 120LB and 125LB? (3 decimal places)
What is the mean of Z distribution? (0 decimal places)
i) The correct characteristics of the t distribution with 10 degrees of freedom:
a) symmetric around 0
c) it is taller than t distribution with 5 degrees of freedom
d) variance is 10/8
ii) If the weight of products ~ N(120LB, 30LB) then the probability that the weight of the product is larger than 130 LB is 0.369
iii) For t with 50 degrees of freedom, the 99th percentile of t is 2.403
iv) For t with 50 degrees of freedom, the probability that t has a value larger than 1.2 is 0.118
v) If the weight of products ~ N(120LB, 30LB) then the 95th percentile of the weight of the product is 169.35
vi) For t with 50 degrees of freedom, the probability that t has a value between -1.5 and -0.5 is 0.24
vii) If the weight of products ~ N(120LB, 30LB) then the chance that the weight of the product is between 120LB and 125LB is 0.066
vii) The mean of Z distribution is 0.
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