In: Statistics and Probability
19
degrees of freedom. ComputeP≤t−1.22
. Round your answer to at least three decimal places.10
degrees of freedom. Find the value ofc
such that=P<−c<tc0.90
. Round your answer to at least three decimal places.
Solution:
Question 1)
Given: a t distribution with 19 degrees of freedom.
Compute:
P( t ≤ −1.22 ) =............?
Use following Excel command:
=T.DIST(t , df, cumulative)
=T.DIST(-1.22,19,TRUE)
=0.118696
=0.119
Thus P( t ≤ −1.22 ) = 0.119
Also we can use TI 84 plus calculator :
Press 2ND and VARS
Select tcdf(
Enter numbers:
Click on Paste and press Enter two times.
thus we get:
P( t ≤ −1.22 ) = 0.118696
P( t ≤ −1.22 ) = 0.119
Question 2)
a t distribution with 10 degrees of freedom. Find the value of c such that:
P(−c< t < c) = 0.90
Since area between -c to c is 0.90
then area in two tails = 1 - 0.90 = 0.10
Thus use following excel command:
=T.INV.2T(probability, df)
=T.INV.2T(0.10,10)
=1.812461
=1.812
thus c = 1.812
that is: P( -1.812 < t < 1.812)= 0.90
Use following steps inTI 84:
Press 2ND and VARS
Select invT(
Enter numbers:
Here we enter area in left tail = 0.10 / 2 = 0.05
thus
thus absolute value of c = 1.812